Question

Даны векторы а{-4; 3; 0} b{6; 0; -8} c{0; -4; -3} Вычислите: 1. a-b 2. b+c 3. |a-b| 4. 3|a|+2|c| 5. a-2b-4c

Answer 1

1. a-b = (-4-6;3-0;0-(-8)) = (-10;3;8)

2. b+c = (6+0;0+(-4);-8+(-3)) = (6;-4;-11)

3. |a-b| = √((-10)²+3²+8²) = √(173)

4. 3|a|+2|c| = 3√(4²+3²+0²) + 2√(0²+4²+3²) = 3*5+2*5 = 5*5 = 25

5. a-2b-4c = (-4;3;0) - 2*(6;0;(-8)) - 4*(0;-4;-3) = (-4;3;0) - (12;0;-16) - (0;-16;-12) = (-4+12-0;3-0-(-16);0-(-16)-(-12)) = (8;19;28)