2х^2-у^2=34
xy=20
y=20/x
2x^2-(20/x)^2=34
2x^2-400/x^2-34=0
2x^4-34x^2-400=0
Замена: x^2=t
2t^2-34t-400=0
t^2-17t-200=0
D=289+800=1089
t1=(17+33)/2=25
t2=(17-33)/2=-8 - не подходит
Обратная замена:
x^2=25
1) x=5, y=4
2) x=-5, y=-4
Sinα<span>=-0.6; Сos</span>β<span>=0.28 и </span>π<α<1.5π; 1.5π<β<1.5π
10Сos(α+β<span>) = ?
Решение
Cos(</span>α + β) = CosαCosβ - SinαSinβ
Cos²α= 1 - Sin²α = 1 - 0,36 = 0,64,⇒ Cosα = -0,8
Sin²β = 1 - Cosβ = 1 - 0,0784 = 0,9216, ⇒ Sinβ = - 0,96
10Сos(α+β) = 10(0,28*(-0,8) - (-0,6)*(-0,96)) = 10(-0,224 - 0,576) = 10*(-8)=
= -80
Sqrt(25-x)^2=4
25-x=4
x=21
2)
sqrt(x^2)-81=12
x-81=12
x=93
(3 7/11) / ( 2+ (2/11 + 4/19)) = (3 7/11) / ( 2+ ( 19*2/209 + 44/209))=
(3 7/11) / ( 2 82/209) = (3 7/11) / (500/209)= 40/11 * 209/500 = 40*209/(11*500) =
= 4*19/50 = 0.08 *19 = 1.52