Question

Решите уравнение (х-22)^2+(х+2)^2=2х^2

Answer 1

Х^2 - 44x +484 + x^2+4x+4 -2x^2 = 0
-40x+488=0
-40x = -488
x = 12,2

Answer 2

(х-22)^2+(х+2)^2=2х^2
x²-44x+484+x²+4x+4=2x²
-40x+488=0
40x=488
x=488/40 = 122/10 = 12.2