<span>1) 4P+5O2 = 2P2O5</span>
<span>2) P2O5 + 3H2O = 2H3PO4</span>
<span>3) H3PO4 + 3KOH = K3PO4 + 3H2O</span>
Какое количество вещества кислорода требуется для сжигания 0.5 моль магния
n(O2)=0.5 моль
<span><span>4 <span>Fe</span></span>+<span>6<span>H2O</span></span>+<span>3<span>O2</span></span> → <span>4<span>Fe<span>(OH)</span><span>3</span></span></span></span><span><span>
Fe2<span>(SO4)</span>3</span>+<span>6<span>NaOH</span></span> → <span>2<span>Fe<span>(OH)</span>3</span></span>+<span>3<span>Na2SO<span>4
</span></span></span></span>
.............................
CH3COH+ Ag2O---> CH3COOH +2Ag
1) v(CH3COH)= m|M= 18| 44=0,41 моль