<span><span>у</span>=<span><span>(<span><span><span>2⋅x</span>4</span>⋅x+3</span>)</span>′</span>=</span><span>у=<span><span>(<span><span><span>2⋅x</span>4</span>⋅x</span>)</span></span></span><span>у=<span><span>(<span><span>2⋅x</span>4</span>)</span>′</span>⋅x+<span><span>2⋅x</span>4</span></span><span>у=<span><span><span>(<span>2⋅x</span>)</span>′</span>4</span>⋅x+<span><span>2⋅x</span>4</span></span><span><span>24</span>⋅x+<span><span>2⋅x</span>4</span></span>
Ответ:
<span><span>у</span>=<span>24</span>⋅x+<span><span>2⋅x</span>4</span></span>
Увеличить значит прибавить.
24+7=31
если (А/В)/С раскрыть, тогда получится (А/С)/(А/В), тогда (А/С)/(А/В)=(А/С)/(А/В)
х-7 14/19=15 24/19-10 13/19
х-7 14/19=5 11/19
х=5 11/19+7 14/19
х=12 25/19
х=13 6/19