<span>2NaOH+N2O5 = 2NaNO3 + H2O</span>
<span>2Na(+) + 2OH(-) + N2O5 = 2Na(+) + 2NO3(-) + H2O</span>
<span>2OH(-) + N2O5 = 2NO3(-) + H2O</span>
<span>2NaOH+H2SO4 = Na2SO4 + 2H2O</span>
<span>2NaOH+FeCl2 = Fe(OH)2<span>↓ + 2NaCl</span></span>
<span>AgOH + HNO3 = AgNO3 + H2O</span>
<span>2)азот
NH3
...................................................</span>
1)
дано
n(CH3COOH)=0.6 mol
Na
-----------------------
V(H2)-?
0.6 mol Xmol
2CH3COOH+2Na-->2CH3COONa+H2↑
2mol 1mol
0.6/2=X/1
X=0.3 mol
V(H2)=n*Vm=0.3*22.4=6.72 л
ответ 6.72 л
2)
дано
n(CH3COOH)=0.75 mol
Na
η=0.8
-----------------------
m(практCH3COONa)-?
0.75 mol Xmol
2CH3COOH+2Na-->2CH3COONa+H2↑
n(CH3COOH)=n(CH3COONa)=0.75 mol
M(CH3COONa)=82 g/mol
m(CH3COONa)n*M=0.75*82=61.5g - теоретический выход
m(пракCH3COONa)=m(теор)*η=61.5*0.8=49.2 g
ответ 49.2 g