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X+O2=CO2+SO2
C+O2=CO2 m(C)=12*0.385/44=0.105 гр n(C)=0.105/12=0.00875 моль
S+O2=SO2 m(S)=32*0.392/22.4=0.56 гр n(S)=0.56/32=0.0175 моль
n(C):n(S)=0.00875:0.0175=1:2 CS2
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дано
m(CaC2) = 1000 g
Vпракт (C2H2) = 220 L
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η(C2H2)-?
CaC2+2H2O-->Ca(OH)2+C2H2
M(CaC2) = 64 g/mol
n(CaC2) = 1000 / 64 = 15.625 mol
n(CaC2) = n(C2H2) = 15.625 mol
Vтеор(C2H2) = n*Vm = 15.625 * 22.4 = 350 L
η(C2H2) = Vпракт (C2H2) / Vтеор(C2H2) * 100%
η(C2H2) = 220 / 350 * 100%= 62.86 %
ответ 62.86%