Question

Помогите решить пожалуйста 1) (log₃72 - log₃18)*log₄3 + 2 2) (log₂₆5^log₅169 + log₂₆4)² - 17^4log₂₈₉3

Answer 1

$(log _{3}72-log _{3}18)*log _{4}3+2=log _{3} \frac{72}{18}*log _{4} 3+2=log _{3}4*log _{4}3+2=$$1+2=3$

$(log _{26} 5 ^{log _{5} 169}+log _{26}4) ^{2}-17 ^{4log _{289}3 } =(log _{26}169+log _{26}4) ^{2}-$$(17 ^{2}) ^{2log _{289}3 }=log _{26}(169*4)-289 ^{log _{289}6 } =log _{26}676-6=2-6=-4$