X^2-4x<0
X(x-4)<0
y=x(x-4)
0=x(x-4)
x=0 x-4=0
x=4
x∈(0;4)
3 sqrt2 sin (π/2 + x) - 2 = 2cos^2 x
3 sqrt2 cos x - 2 = 2cos^2 x
2cos^2 x - 3 sqrt2 cos x + 2 = 0
cos x = t
2t^2 - 3 sqrt2 t + 2 = 0
D = 18 - 16 = 2
t = 3 sqrt2 (+/-) sqrt2 / 4
t1 = sqrt2
t2 = sqrt2 / 2
cos x = sqrt2 => решений нет
cos x = sqrt2 / 2 => х = (+/-)π/4 + 2πn, n € Z
<span>(а+1)(а+2)(а-3)-2(а-4)+5</span>
<span><span>(а+1)(а+2)(а-3)-2a+13</span></span>
(a²+3a+2)(a-3)-2a+13
(a³-3a²+3a²-9a+2a-6)-2a+13
(a³-7a-6)-2a+13
a³-9a+7
У= кх+m
4k+m= -5
-2k+m= 19 |*2
4k+m= -5
-4k+2m= 38
3m= 33
m= 11
y= kx+11
4k+11= -5
4k= -16
k= -4
y= - 4x+11