Question

Расчет цепи с конденсаторами

Answer 1

2 мкФ=2*10^-6 Ф
1 мкФ=10^-6 Ф
3 мкФ=3*10^-6 Ф
0.5 мкФ=0.5*10^-6 Ф

$C_{67} = \frac{ C_{6}* C_{7}}{C_{6}+ C_{7}}$
$C_{567} = C_{67} + C_{5}$
$C_{2567} =\frac{ C_{567}* C_{2}}{C_{567}+ C_{2}}$
$C_{34} =\frac{ C_{3}* C_{4}}{C_{3}+ C_{4}}$
$C_{234567}= C_{34}+C_{2567}$
$C= \frac{C_{1}*C_{234567}}{C_{1}+C_{234567}}$