V=abc= 18*16*5=1440 см³
V=16*23*25=9200см³
А как именно составлять схему?
1)<span>1/12+3 4/15</span>=3+<span>1/12</span>+<span>4/15</span> = 3+<span>1·5/12·5</span>+<span>4·4/15·4</span>=3+<span>5/60</span>+<span>16/60</span>=3+ <span>5+1660</span>=3 <span>21/60</span>=3 <span>7·3/20·3</span>=3 <span>7/20</span> = 3.35
2)3 19/21+2 2/3=5+<span>19/21</span>+<span>2/3</span>=5+<span>19·1/21·1</span>+<span>2·7/3·7</span>=5+1<span>9/21</span>+<span>14/21</span>=5+ <span>19+14/21</span>=5 <span>33/21</span>=5 11·3/7·3=5 <span>11/7</span>=5 <span>4+1·7/7</span>=6 <span>4/7
</span>3)5*5 4/5=5·4+5·5/5=5<span>·</span><span>29/5</span> = <span>5·29/5</span> = <span>145/5</span> = <span>29·5/5</span><span> = 29
</span>И все в таком роде
4)<span>1 7/9*1 2/3=2 26/27
</span>5)<span>5 1/10-1 1/16=4 3/80
</span>6)<span>4-2/7=3 5/7
</span>7)<span>4/9+1 2/3=2 1/9
</span>8)5 3/8-2 11/16=2 11/16
Колькулятор)
14490/70*31=6417
∠B=180°-30°-75°=75°=>ΔABC-равноб.
AC=AB=4,5
находим 3 сторону по теореме cos
BC²=AC²+AB²-2*AC*CB*cos30
BC²=4,5²+4,5²-2*
![\frac{ \sqrt{3} }{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D+)
*4,5²=4,5²+4,5²-√3*4,5²=2*4,5²-√3*4,5²=4,5²(2-√3)=>BC=4,5*
![\sqrt{2- \sqrt{3} }](https://tex.z-dn.net/?f=+%5Csqrt%7B2-+%5Csqrt%7B3%7D+%7D+)