<span>C6H5NO2 + 3H2 = C6H5NH2 + 2H2O</span>
<span>n = m/M</span>
<span>M(<span>C6H5NO2</span>) = 123 г/моль</span>
<span>n(<span>C6H5NO2</span>) = 123 г / 123 г/моль = 1 моль</span>
<span>n(<span>C6H5NO2</span>) = n(<span>C6H5NH2</span>) = 1 моль</span>
<span>m = n*M</span>
<span>M(<span>C6H5NH2</span>) = 93 г/моль</span>
<span>m(<span>C6H5NH2</span>) = 1 моль * 93 г/моль = 93 г</span>
<span><span>η</span> = <u>m практич </u> * 100%<u>
</u></span>
<span><u /> m теоритич</span>
<span><span>η<span>(<span>C6H5NH2</span>)</span> = 88 г / 93 г * 100 % = 95 %</span></span>
<span><span>Ответ: 95 %</span></span>