Question

Log3(5-x)+log3(-1-x)= --3

Answer 1

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Answer 2

$log_3(5-x)+log_3(-1-x)=3\\\left \{ {{5-x>0} \atop {-1-x>0}} \right. =>\left \{ {{x<5} \atop {x<-1}} \right. =>x<-1\\log_3((5-x)(-1-x))=3\\log_3(-5-5x+x+x^2)=3\\log_3(x^2-4x-5)=3=>x^2-4x-5=3^3=>x^2-4x-32=0\\D_1=4+32=36\\x_1=2+6=8\\x_2=-4\\x<-1=>x=-4$