Question

1.1. Вычислить производную функции: у= (1/3)х6+7х2 – 2х +1, у′(-1)=?; у=cos x – (2/π)x2+1, у′(π/2)=?; 3) y=10x/ln10 – 2/x +3x – 12, у′(-1)=?.

Answer 1

Ответ:

1.

y = 1/3 * x^6 + 7 x^2 - 2x + 1.

y' = 2 x^5 + 14 x - 2

y'(-1) = -2 - 14 - 2 = - 18

2.

y = cos(x) - 2/pi * x^2 + 1.

y' = -sin(x) - 4/pi * x

y'(pi/2) = - 1 - 8 = - 9.

3.

y = 10x/ln(10) - 2/x + 3x - 12.

y' = 10/ln(10) + 2 / x^2 + 3

y'(-1) = 10 * lg(e) + 5.