<em><span><span>2NH4Cl + Ca(OH)2 => 2NH3↑ + 2H2O + CaCl2</span></span></em>
11-д
13-е
14-в NH3+HNO3=NH4NO3
Ca+2H2O=Ca(OH)2+H2 вот так..
m(H2)=2*20/40=1г
Дано
m(ppaKOH)=100 g
W(KOH)=14%
---------------------------
m(Cu(OH)2)-?
m(KOH)=100*14%/100%=14 g
14 X
2KOH+CuSO4-->K2SO4+Cu(OH)2
2*56 98
M(KOH)=56 g/mol
M(Cu(OH)2=98 g/mol
14 / 112 = X / 98
X=12.25 g
ответ 12.25 г