Ху(х+у) - 2(х+у)=(х-2)(х+у)
Y = - 3x^2 - 5x - 2
y = 0
- 3x^2 - 5x - 2 = 0
D = 25 - 24 = 1 ; V D = 1
X1 = ( 5 + 1 ) : ( - 6 ) = - 1
X2 = ( 5 - 1 ) : ( - 6 ) = - 2/3
x = 0
y = - 2
Ответ ( 0 ; - 2 ) ; ( - 1 ; 0 ) ; ( - 2/3 ; 0 )
ОДЗ
7-3x>0⇒3x<7⇒x<7/3
7-3x≠1⇒3x≠6⇒x≠2
9x²-6x+1>0⇒(3x-1)²>0⇒3x-1≠0⇒3x≠1⇒x≠1/3
x∈(-∞;1/3) U (1/3;2) U (2;2 1/3)
1)x∈(-∞;1/3) U (1/3;2)
9x²-6x+1≥(7-3x)²
(3x-1)²-(7-3x)²≥0
(3x-1-7+3x)(3x-1+7-3x)≥0
(6x-8)*6≥0
6x-8≥0
6x≥8
x≥1 1/3
x∈[1 1/3;2)
2)x∈(2;2 1/3)
x≤1 1/3 решения нет
Ответ x∈[1 1/3;2)
1) (a-z)(a+z)=a²+az-za-z²=a²-z²
2) (a+p)(a-p)=a²-ap+pa-p²=a²-p²
3) (f+5)(5-f)=5f-f²+25-5f=-f²+25=25-f²
4) (10+b)(10-b)=100-10b+10b-b²=100-b²
5) (7x-8y)(7x+8y)=49x²+56xy-56yx-64y²=49x²-64y²
6) (1-k)(k+1)=k+1-k²-k=1-k²
<span>7) (3d</span>²<span>-4p)(3d</span>²<span>+4p)=9d</span>⁴+12pd²-12pd²-16p²=9d⁴-16p²
= c³-9c²d+27cd²-27d³+12c²d-36cd² = c³+3c²d-9cd²-27d³