А) 2HCOOH + Zn = (HCOO)₂Zn + H₂
б)2CH₃COOH + CaCO₃ = (CH₃COO)₂Ca + CO₂ + H₂O
в)CH₃COH + Ag₂O = CH₃COOH + 2Ag
Na2CO3<span> ↔ 2Na</span>+<span> + CO</span>32-<span>
</span>2Na+<span> + CO</span>32-<span> + H</span>2O ↔ HCO3-<span> + OH-</span>+ 2Na<span>+
</span>CO32-<span> + H</span>2O ↔ HCO3-<span> + OH-
</span>Na3PO4<span> ↔ 3Na</span>+<span> + PO</span>4<span>3-
</span>3Na+<span> + PO</span>43-<span> + H</span>2O ↔ HPO42-<span> + OH-</span><span> + 3Na</span>+<span>
</span>PO43-<span> + H</span>2O ↔ HPO42-<span> + OH-
</span>Na2SO4<span> ↔ 2Na</span>+<span> + SO</span>42-<span>.
</span>NaNO3<span> ↔ Na</span>+<span> + NO</span>3-
Zn + 2HCl = ZnCl₂ + H₂
по уравнению реакции
m(ZnCl₂)/M(ZnCl₂)=m(Zn)/M(Zn)
теоретическая масса соли
m(ZnCl₂)=M(ZnCl₂)m(Zn)/M(Zn)
выход соли
w=m₀(ZnCl₂)/m(ZnCl₂)=m₀(ZnCl₂)M(Zn)/{M(ZnCl₂)m(Zn)}
w=13г*65г/моль/{136г/моль*6,5г}=0,956 (95,6\%)