2Cu(NO3)2*xH2O=2CuO+2xH2O+4NO2+O2
4.3294/(188+18x)=1.4321/80
=> x=3
Cu(NO3)2*3H2O
Убывает .......................................................................
W(H) = Ar(H) * n / Mr(H2O) *100% = 1*2 / 18 *100% =11%
W(H) = Ar(H) *n / Mr(NH3) *100% = 1*3 / 17 *100% =18%
W(H) =Ar(H) *n / Mr(CH4) *100% = 1*4 / 16 *100%=25%
Ответ: H2O, NH3, CH4