Алкин - это СхН2х-2
М(алкина) = плотность*молярный объём = 2,41*22,4 = 54 г/моль
14х-2=54
х=4
С4Н6 - бутин.
СН3-СНCl-CH3+NaOH(спирт. р-р)-->CH2=CH-CH3+NaCl+H2O
Масса соли (NaCl) равна 58,4г. Масса воды =18г
2CH4=C2H2+3H2
C2H2+H2=C2H4
C2H4+H2O=C2H5OH
C2H5OH+CH3COOH=CH3COOC2H5+H2O
1) <span> 6CO</span>2<span> + 5H</span>2<span>O = C</span>6<span>H</span>10<span>O</span>5<span>+ 6O</span>2<span>.</span>
<span> </span>
<span><span> C6H1206 = 2C2H5OH+2CO2</span></span>
<span><span> </span></span>
<span><span> <span>C2H5OH + O2 = CO2 +H2O</span></span></span>
<span><span><span>2) <span>2CH4 = C2H2 +3H2</span></span></span></span>
<span><span><span><span> </span></span></span></span>
<span><span><span><span><span> 3C2H2(катализатор активированный уголь) = C6H6</span></span></span></span></span>
<span><span><span><span><span> </span></span></span></span></span>
<span><span><span><span><span><span> С6Н6 +HNO3 =С6Н5NO2 +H2O (реакция нитрования)</span></span></span></span></span></span>
<span><span><span><span><span><span><span> 2C6H5NO2 + 2NH3OH -> 2C6H5NH2 + 2HNO3 + H2</span></span></span></span></span></span></span>
C6H5NH2 + 3Br2 = (+H2O, 20 градусов) C6H2(NH2)Br3 (2,4,6 -триброманилин, осадок) + 3HBr.
<span><span><span><span> </span></span></span></span>