<span>tg(-arcsin(3/5) +П- arccos(1/корень из 2)) =tg(-arcsin(3/5) +3.4*П)</span>
1+sin2a/(sina+cosa)=(sina+cosa)^2/(sina+cosa)=sina+cosa
<span>1)(a x^2+b x^2)x^3 = a x^5 + b x^5</span>
<span><span>2)(x x^2-y x^2)x^3 = x^6 - y x^5</span></span>
<span><span><span>3)(2m x^2-3n x^2)x^3 = 2m x^5 - 3n x^5</span></span></span>
<span><span><span><span>5)(4m x^3+n x^2)x^3 = 4m x^6 + n x^5</span></span></span></span>
<span><span><span><span><span>6)(10p x^4-6q x^2)x^3 = 10p x^7 - 6q x^5</span></span></span></span></span>
<span><span><span><span><span><span>7)(7u x^3-9v x^4)x^3 = 7u x^6 - 9vx^7</span></span></span></span></span></span>
<span><span><span><span><span><span><span>8)(10x x^3+3y x^2)x^3 = 10x^7 + 3y x^5</span></span></span></span></span></span></span>
Так помоему. потом сама найдешь <span>общую точку</span>
=( 2корень из 12)в квадрате /12 = 4*12/12= 4 (если я правильно поняла задание)