1)0.8
2)8
3)2.5298221
3 иррац.
(1/3)^6 × 27^2 = 3^(-1 × 6) × (3^3)^2 = 3^(-6) × 3^(3×2) =
= 3^(-6) × 3^6 = 3^( -6 + 6) = 3^0 = 1
Решение
(1/3a^2b)^3*(9ab^3)^3 = (1/3)³ * a⁶ * b³ * 3⁶ * a³ * b⁹ =
= 3³ * a⁹ * b¹² =27 * a⁹ * b¹²
1) -2*(-4)^2+3*(-4)-5=-49
2) -2*(-1.4)^2+3*(-1.4)-5=-13.12
3) -2*(-1)^2+3*(-1)-5=-10
4) -2*(-5)^2+3*(-5)-5=-70
5) -2*2.5^2+3*2.5-5=-10
6) -2*5^2+3*5-5=-40