2.945•22+1,549•22-20,9=77,968
<span>x²+4x-5=0
</span>
D=16+20=6²
х₁=(-4+6)/2=1 больший
х₂=(-4-6)/2=-5
<span />
AB^2=(9-2)^2+(10-3)^2+(-5-(-5))^2=98
AB=√98
AC^2=(9-2)^2+(3-3)^2+(2-(-5))^2=98
AC=√98
BC^2=(2-2)^2+(10-3)^2+(2-(-5))^2=98
BC=√98
AB=AC=BC=√98 => треугольник равносторонний
15кв. м. 38 кв.дм.+47кв.дм.=15кв.м.85кв.дм.
125_250,375,500,625,750,875,