Да, Q= -81 кДж/моль, реакция является эндотермической
1. CH4 + 2O2 = CO2 + 2H2O
2. CO2 + CaO = CaCO3
3. CaCO3 + H2CO3 = Ca(HCO3)2
4. Ca(HCO3)2 + Ca(OH)2 = 2CaCO3 + H2O
5. CaCO3 = CaO + CO2
6.<em>C</em><em>O</em>2<span> + </span><em>C</em><span> = </span><span>2</span><em>C</em><em>O</em>
A-1
Б-3
В-4
2Li+2H2O=2LiOH+H2
2Li+Cl2=2LiCl
SO2+H2O=H2SO3
SO2+K2O=K2SO3
Ba(OH)2+H2SO4=BaSO4+2H2O
Ba(OH)2+2NH4NO3=Ba(NO3)2+2NH4OH
CH3-CH2-COOH + CI2 -(P, t°)-> CH3-CH(CI)-COOH + HCI
CH3-CH(CI)-COOH + NH3 -> CH3-CH(NH2)-COOH + HCI
OH-CH2-CHBr-CH(C2H5)-CH2-CH3