= (3√5-2√5)*√5=3*5-2*5=5
= (√3+√2)²=3+2√6+2=5+2√6
3(7-х)=5+2х
21-3х=5+2х
-3х-2х=5-21
-5х=-16
х=-16:(-5)
х=3,2
<span>а) y=(3x^2-6x+1)/(2x+1)
у' = ((6x -6)*(2x +1) - (3x</span>² -6x +1)*2)/(2x +1)²<span> =
=(12x</span>²-12x +6x -6 -6x² +12x -2)/(2x +1)² = (6x²+6x -8)/(2x +1)²<span>
b)y=3*3√x -5/x+ 1/x^2 = 9</span>√x -5x^-1 + x^-2
y' = 9/(2√x) + 5x^-2 - 2x^-3 = 9/(2√x) +5/x² - 2/x³