|x-3|=х-3
х-3+0.5=0.5
х=0.5-0.5+3
х=3
А) √2cosx = 1
cosx=√2/2
x=π/4+2πk, k∈Z
x=-π/4+2πk, k∈Z
б) sinx+cosx=0 |: cosx≠0
tgx=-1
x=-π/4+πk, k∈Z
с) 2cos²x-sinx=-1
2(1-sin²x)-sinx+1=0
2-2sin²x-sinx+1=0 |:(-1)
2sin²x+sinx-3=0
sinx=y, |y|≤1
2y²+y-3=0
y=-1,5 - п.к.
y=1
sinx=1
x=π/2+2πk,k∈Z
2. ctg(π/2+x)>√3
-tgx>√3
tgx<√3
x∈(-π/2+πk;π/3+πk), k∈Z
<span>1. 5:7=х:91
7*x=5*91
7x=455
x=455:7
x=65
2. </span><span>а: 2 3/23=3 2/7:1/4
2 3/23* 3 2/7=a*1/4
49/23*23/7=1/4 a
7=1/4 a
1/4 a=7
a=7: 1/4
a=28
3.</span><span>у/0͵8=23/4
</span>4y=0.8*23
4y=18.4
y=18.4:4
y=4.6<span>
</span>4. 3+z/8=6/11
(3+z)*11=8*6
33+11z=48
11z=48-33
11z=15
z=15:11
z=1 4/11
1)455/91=5
2)5863/451=13
3)399/133=3
4)399/82=2
5)261/81=3
6)814/74=11