СnH(2n-6) + Br2 -(FeBr3)-> CnH(2n-5)Br + HBr
m теор(CnH(2n-5)Br)=35,82/0,75=47,76г
28,8/(12n+2n-6) = 47,76/(12n+2n-5+80)
28,8*(14n+75) = 47,76/(14n-6)
403,2n+2160 = 668,64n-286,56
265,44n = 2446,56
n = 9
C9H13 - фенилпропан
Mр-ра=mв-ва/w=30/0,3=100 г
m(H2O)=100-30=70 г
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Fe2(SO4)3 + 6NaOH = 2Fe(OH)3 + 3Na2SO4