Решение
x + y = 40
x*y = 364
y = 40 - x
x*(40 -x) = 364
x∧2 - 40x + 364 = 0
D = (40∧2 - 4*1*364 = 1600 - 1456 = 144
x1 = (40 - 12) / 2 = 14
x2 = (40 + 12) / 2 = 26
y1 = 40 - 14 = 26
y2 = 40 - 26 14
Ответ: (14; 26); (26;14)
3-2х>8х-1 ;
-2х-8х>-3-1 ;
-10х>-4 ;
Х<2,5
Ответ:
Объяснение:
(2-x)^6= (2-x)^4(2-x)² =
=(2^4-4*2³x+6*2²x²-4*2x³+x^4)(4-4x+x²)=
=(16-4*8x+6*4x²-8x³+x^4)(x²-4x+4)=
=(16-32x+24x²-8x³+x^4)(x²-4x+4)=
=(x^4-8x³+24x²-32x+16)(x²-4x+4)=
=x^6-8x^5+24x²-32x³+16x²-4x^5+32x^4-96x³+128x²-64x+
+4x^4-32x³+96x²-128x+64=
=x^6-12x^5+60x^4-160x³+240x²-192x+64
<span>в) -4 <= x - 5 <= 1
-4+5<=x<=1+5
1<=x<=6
г) -8 < 3х + 4 < 1
-8-4<3x<1-4
-12<3x<-3
-4<x<-1
</span>