M(NaCI)=460*0.04=18.4г m₁(H2O)=460г(р-ра)-18.4г=441.6г
m₂(H2O)=441.6г-140г=301.6г m(р-ра)= 301.6+18.4=320г
w(NaCI)= 18.4/320*100%=5,75%
200-80-- 120 второе действие 120+14
CH3-C≡C-CH3<span> + HBr --> CH</span>3-CH=CBr-CH3
CH3-CH=CBr-CH3<span> + HBr --> CH</span>3-CH2-CBr2-CH3<span> </span>
1) C10H22 -----t----> C7H14 + C3H8
2) C7H14 + H2O ------t, H2SO4 (конц.)----> C7H15OH
3) C7H15OH + HBr -------><--------- C7H15Br + H2O
4) C7H15Br + KOH -----t-----> KBr + H2O + C7H14
5) C7H14 + H2 ------t, p, Ni------> C7H16
6) C7H16 -------t, Cr2O3-------> C7H14 + H2
7) C7H14 + H2O ------t, H2SO4 (конц.)----> C7H15OH
8) C7H15OH + 11O2 ---------> 7CO2 + 8H2O +Q
17.92 Х
2С₂Н₆ + 7О₂ = 4СО₂ + 6Н₂О
2*22,4 7*22.4
Х= (17.92*7*22,4)/2*22,4=62,72(л) кислорода