1)С+2Н2=СН4
2)СН4+Br2=СН3Br+НBr
3)СH3Br+С3Н7Na=С4Н10<span> + NaBr</span>
4) С4Н10+<span>HO-NO2 = </span>C4H9NO2
1.
21.8 г x г<span>
C2H5Br + NaOH </span>→ C<span>2H5OH + NaBr
109 г/mol 46 г/mol
x = 21.8 * 46 / 109 = 9.2 г
2.
18.4 г x г
C2H5OH + CuO </span>→ CH3CHO + Cu↓<span> + H2O
46 г/mol 44 г/mol
</span>x = 18.4 * 44 / 46 = 17.6 г
3.
73.6 г x л
2<span>C3H5(OH)3</span><span> + </span>6K → 2<span>C3H5O3K3</span><span> + </span>3<span>H2</span>↑
184 г/mol 67.2 л/mol
x = 73.6 * 67.2 / 184 = <span>26,88 л </span>≈ 27 л
( = Это не точно = )
Ответ:2NaOH+CuSO4=Cu(OH)2+NaSO4
Объяснение: