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Answer 1

$\frac{3}{20} + \frac{2}{15} =\frac{3*3}{20*3} + \frac{2*4}{15*4} =\frac{9}{60} + \frac{8}{60} =\frac{9+8}{60}= \frac{17}{60} \\ \\ \frac{17}{32} - \frac{5}{12} = \frac{17*3}{32*3} - \frac{5*8}{12*8} = \frac{51}{96} - \frac{40}{96} =\frac{51-40}{96} =\frac{11}{96} \\ \\ \frac{11}{28} + \frac{9}{14} =\frac{11}{28} + \frac{9*2}{14*2} = \frac{11+18}{28} = \frac{29}{28} =1 \frac{1}{28}$

$\frac{35}{36}- \frac{41}{45} =\frac{35*5}{36*5}- \frac{41*4}{45*4} =\frac{175}{180}- \frac{164}{180} = \frac{11}{180} \\ \\ 3 \frac{21}{25} +1 \frac{2}{5}= 3 \frac{21}{25}+ 1 \frac{2*5}{5*5}=3 \frac{21}{25} +1 \frac{10}{25}= (3+1) + (\frac{21}{25}+\frac{10}{25})=4 \frac{31}{25} = \\ \\ =4\frac{25+6}{25} =5 \frac{6}{25}$

$4 \frac{13}{16} -2 \frac{3}{8} =4 \frac{13}{16} -2 \frac{6}{16} =2 \frac{7}{16} \\ \\ 5 \frac{5}{6} - \frac{31}{48} =5 \frac{5*8}{6*8} - \frac{31}{48} =5 \frac{40}{48} - \frac{31}{48} =5 \frac{40-31}{48} =5\frac{9}{48} \\ \\ 6 \frac{4}{7} -2 \frac{37}{77} =6 \frac{4*11}{7*11} -2 \frac{37}{77} =(6-2)+ \frac{44-37}{77} =4 \frac{7}{77} =4 \frac{7:7}{77:7} =4 \frac{1}{11}$