Дано F1=6 Н F2=12Н x- ?
из условия равновесия F1*d1=F2*d2
F1*x=F2*(L-x)
6*x=12*(24-x)
x=48-2*x
x=16 см ( от точки приложения силы F1)
Находим эквивалентное сопротивление, начиная с точки, наиболее удаленной от места подключения.
![R_{56}=R5+R6=R+R=2R=2*8=16 \ (O_M) \\ R_{456}= \frac{R_4*R_{56}}{R_4+R_{56}}= \frac{8*16}{8+16}= \frac{128}{24}= \frac{16}{3} \ (O_M) \\ R_{3456}=R_3+R_{456}=8+\frac{16}{3}= \frac{24+16}{3}= \frac{40}{3} \ (O_M) \\ R_{23456}= \frac{R_2*R_{3456}}{R_2+R_{3456}}= \frac{8* \frac{40}{3}}{8+ \frac{40}{3}}= \frac{\frac{320}{3}}{ \frac{64}{3}}= \frac{320}{64}=5 \ (O_M) \\ R_{123456}=R_1+R_{23456}=8+5=13 \ (O_M)](https://tex.z-dn.net/?f=R_%7B56%7D%3DR5%2BR6%3DR%2BR%3D2R%3D2%2A8%3D16+%5C+%28O_M%29+%5C%5C+R_%7B456%7D%3D+%5Cfrac%7BR_4%2AR_%7B56%7D%7D%7BR_4%2BR_%7B56%7D%7D%3D+%5Cfrac%7B8%2A16%7D%7B8%2B16%7D%3D+%5Cfrac%7B128%7D%7B24%7D%3D+%5Cfrac%7B16%7D%7B3%7D+%5C+%28O_M%29+%5C%5C+R_%7B3456%7D%3DR_3%2BR_%7B456%7D%3D8%2B%5Cfrac%7B16%7D%7B3%7D%3D+%5Cfrac%7B24%2B16%7D%7B3%7D%3D+%5Cfrac%7B40%7D%7B3%7D+%5C+%28O_M%29+%5C%5C+R_%7B23456%7D%3D+%5Cfrac%7BR_2%2AR_%7B3456%7D%7D%7BR_2%2BR_%7B3456%7D%7D%3D+%5Cfrac%7B8%2A+%5Cfrac%7B40%7D%7B3%7D%7D%7B8%2B+%5Cfrac%7B40%7D%7B3%7D%7D%3D+%5Cfrac%7B%5Cfrac%7B320%7D%7B3%7D%7D%7B+%5Cfrac%7B64%7D%7B3%7D%7D%3D+%5Cfrac%7B320%7D%7B64%7D%3D5+%5C+%28O_M%29+%5C%5C+R_%7B123456%7D%3DR_1%2BR_%7B23456%7D%3D8%2B5%3D13+%5C+%28O_M%29++++)
Ответ: 13 Ом
А по подробнее вопрос можно?
N=A/t=mdgh/t=pVgh/t=1000*180*10*10/36000=50Вт
Дано
=10m
V=180m3
t=36000c
p=1000kg/m3
g=10m/c2
N?