Question

Нужно решение задач А13 и А14

Answer 1

А14) Закон Бойля - Мариотта : PV=const

P1V1 = P2V2

P1V1 = (P1 + ΔP)*(V1 - 0,25V1)

P1V1 = (P1 + ΔP)*0,75V1

P1 = 0.75(P1 + ΔP)

P1 = 0.75P1 + 0.75*ΔP

0.25P1 = 0.75*ΔP

P1 = 3*ΔP = 3*5 = 15 кПа

А13) $v = \sqrt{\frac{3kT}{m_{0}}}$ =>

$\frac{v_{2}}{v_{1}} = \frac{\sqrt{\frac{3kT_{2}}{m_{0}}}}{\sqrt{\frac{3kT_{1}}{m_{0}}}} =\sqrt{\frac{T_{2}}{T_{1}}}$ =>

$v_{2} =v_{1} *\sqrt{\frac{T_{2}}{T_{1}}} = 400*\sqrt{\frac{363}{300}} = 440$

Ответ: 4) 440 м/с