Дано
m(NH3) = 500 г
Решение
n(NH3) = m(NH3) / M(NH3) = 500 / 17 = 29.41 моль
N2 + 3H2 = 2NH3
n(H2) = 1.5n(NH3) = 1.5 * 29.41 = 44.115 моль
n(N2) = 0.5n(NH3) = 0.5 * 29.41 = 14.705 моль
V(H2) = n(H2) * Vm = 44.115 * 22.4 = 988.176 дм3
V(N2) = n(N2) * Vm = 14.705 * 22.4 = 329.392 дм3
V(H2) = n(H2) * Vm = 44.115 * 22.4 = 988.176 дм3
V(N2) = n(N2) * Vm = 14.705 * 22.4 = 329.392 дм3
Ответ:
V(H2) = 988.176 дм3
V(N2) = 329.392 дм3
2)H2SO4,Al2(SO4)3,Na2SiO3,H3PO4,Mg(NO3)2,Al2O3, <span>ZnCl<span>2
3)</span></span><span>Mg + H2SO4 → MgSO4 + H2-</span><span>сульфат магния
</span><span>Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O-</span>нитрат меди(II)
Cu + 2HCl t→ CuCl2 + H2-хлорид меди(II )
<span>3CaO + 2H3PO4 → Ca3(PO4)2 + 3H2O-</span>ортофосфат кальция
<span>Zn + 2HCl → ZnCl2 + H2</span><span> хлорид цинка
3)</span><span>KOH + HNO3 → KNO3 + H2O
</span><span>2 Al + 2 H3PO4 </span>→<span>2 AlPO4 + 3 H<span>2
</span></span><span>Ca + 2HCl → CaCl2 + H2
7)</span><span>Al2O3 + 6 HCl </span>→<span>2 AlCl3 + 3 H2O
</span><span>Al2O3 + 3 H2 </span>→<span> 2 Al + 3 H2O
</span><span>K2O + H2SO4 </span>→<span> H2O + K2SO<span>4
</span></span><span>3 Mg + 2 AlCl3 </span>→<span>2 Al + 3 MgCl2</span>
По формуле m=M•n
144=M*0,75
Отсюда: M=144:0.75=192 г/моль
CH3-CH(C2H5)-C(C2H3)(C2H5)-CH(C2H5)-CH3
Ca(OCl)2 + 4HCl = CaCl2 + 2Cl2 + 2H2O, баланс:
2Cl+1 +2e- = Cl2 | 2 | 2 | 1 |
2Cl- -2e- = Cl2 | 2 | | 1 |.