Х²-4ху+4у²=(х-2у)²
(14 16/17 - 2*5 8/17)²= (14 16/17 - 10 16/17)² = 4²=16
(5,666)²- 4*(3,333)²= (5,666)²-2²*(3,333)² =(5,666)²- (6,666)²=
=(5,666- 6,666)*(5,666+6,666)=-1*12,332 = -12,332
Наверно:
(x² +2,5x -18)/(1,5x-6) >1;
(x² +2,5x -18)/(1,5x-6) -1>0
((x² +2,5x -18) -(1,5x-6))/ (1,5x-6)>0 ;
(x² -x-12)/ 1,5(x-4))>0
(x - 4)(x+3)/ 1,5(x-4))>0 * * * x-4≠ 0 ⇔x≠4 * * *
(x+3)/1,5)>0 ;
x+3>0 ;
x >- 3 .
ответ : x∈( -3;∞).