<span>a) AgNO3+ NaCl</span>⇒AgCl↓+NaNO3
<span>Ag</span>⁺+NO3⁻+Na⁺+Cl⁻=AgCl↓+Na⁺+NO3⁻
<span>Ag</span>⁺+Cl⁻=AgCl↓<span>
b) BaCl2+H2SO4</span>⇒BaSO4↓+2HCl
Ba⁺²+2Cl⁻+2H⁺+SO4⁻²=BaSO4↓+2H⁺+2Cl⁻
Ba⁺²+SO4⁻²=BaSO4↓
Дано:
<span>HNO3</span>
<span>Найти: w(H),
w(N), w(O)</span>
Решение:
<span>w(э)
= Ar(э) ∙ n(э)\Mr(в-ва)</span>
<span>Mr
(HNO3) = 1 + 14 + 16∙3 = 63</span>
<span>W(H) = 1
∙ 1\63 = 0,016 или 1,6%
</span><span>W(N) = 14 ∙ 1\63 = 0,22 или 22,2%
</span><span>W(O) = 16 ∙ 3\63 = 0,762 или 76,2%</span>
a)2mgch3coo+h2so4=mgso4+2ch3cooh
b)с чем?
в)сh3cooh+c4h9oh=ch3-coo-c4h9<span> + h2o</span>
<span>2.</span>
<span>2CH4=C2H2+3H2 3C2H2=C6H6 C6H6+3Br2=C6H3Br3+3HBr</span>
2CH₃COOH + Zn = (CH₃COO)₂Zn + H₂
2CH₃COOH + CuO = (CH₃COO)₂Cu + H₂O