ZnCl2+2NaOH=2NaCl+Zn(OH)2
Zn2+ + 2Cl- + 2Na+ + 2OH- = 2Na+ + 2Cl- + Zn(OH)2
Na2S + 2HCl = H2S + 2NaCl
2Na+ + S- + 2H+ + 2Cl- = H2S + 2Na+ + 2Cl-
M=M*n , N=NA(число Авогадро)*n , V=Vm*n
M=12+16*2=44 г/моль
m=44*1,5=66 г
N=6*10^23*1,5=9*10^23
V=22,4*1,5=33,6 л
Вроде так=)
<span><span>2Al</span>+<span>6<span>H2O</span></span>→<span>2<span>AI<span>(OH)</span>3</span></span>+<span>3<span>H2
</span></span></span><span><span>Al<span>(OH)</span>3</span>+<span>3<span>HCl</span></span>→<span>AlCl3</span>+<span>3<span>H2O
</span></span></span><span><span>AlCl3</span>+<span>3<span>H2O</span></span>→<span>Al<span>(OH)</span>3</span>+<span>3<span>HCl
</span></span></span><span><span>Al<span>(OH)</span>3</span>+<span>NaOH</span>→<span>Na<span>[Al<span>(OH)</span>4<span>]
</span></span></span></span>
M(р-ра) = m(в-ва) + m(воды) = 40 + 170 = 210 (г)
Ответ: 210 г