∛x = 10 - x
замена ∛x=t
t = 10 - t³
t³ + t -10 = 0
t³ + 2t² - 2t² - 4t + 5t - 10=0
t²(t - 2) + 2t(t -2) + 5(t-2) = 0
(t -2) (t² + 2t + 5) =0
t=2
∛x=t
x=8
t²+2t+5=0
D=4-20<0 действительных корней нет
Ответ 8
1)2x(2x-y)=0 x=0 x=y/2
2)2x(x-2y²)=0 x=0 x=2y²
3)2x²=3y² x=√3y²/2=y√3/2
4)x²=-y-y² x=√(-y-y²)
9х²<span>+6х+1-3х-1=0
</span>9х²+3х=0
3х(3х+1) = 0
3х = 0
х₁ = 0
3х+1 = 0
3х = -1
х₂ = -1/3