Al2O3+3H2SO4 = Al2(SO4)3+3H2O
M(Al2O3) = 102 г/моль
M(Al2(SO4)3) = 342 г/моль
m(Al2(SO4)3) = (30,6 г * 342 г/моль) : 102 г/моль = 102,6 г
Ответ: 102,6 г
Объясняю сразу:
200 - 100%
х- 65%
1)200:100=2(кг)-в1%
2)65*2=130(кг.)-в 200кг
Ответ: нужно 130 кг меди
Na2CO3<span> ↔ 2Na</span>+<span> + CO</span>32-<span>
</span>2Na+<span> + CO</span>32-<span> + H</span>2O ↔ HCO3-<span> + OH-</span>+ 2Na<span>+
</span>CO32-<span> + H</span>2O ↔ HCO3-<span> + OH-
</span>Na3PO4<span> ↔ 3Na</span>+<span> + PO</span>4<span>3-
</span>3Na+<span> + PO</span>43-<span> + H</span>2O ↔ HPO42-<span> + OH-</span><span> + 3Na</span>+<span>
</span>PO43-<span> + H</span>2O ↔ HPO42-<span> + OH-
</span>Na2SO4<span> ↔ 2Na</span>+<span> + SO</span>42-<span>.
</span>NaNO3<span> ↔ Na</span>+<span> + NO</span>3-