По определению
(0,3)^0=2х+1
1=2х+1
2х=0
Х=0
3√5 = √9*5 = <span>√45
............................</span>
(36m⁸n²k)/(12m²n)=(36/12)m⁸⁻²n²⁻¹k¹=3m⁶n¹k¹=3m⁶nk;
(( 1/a + 1/b)( 1/a^2- 1/ab+ 1/b^2 )( 1/a- 1/b)) / ( 1/a^2 - 1/ab + 1/b^2)- 1/a^2+= (1/a+1/b)(1/a-1/b)- 1/a^2= - (1/b^2) = -4