Question

7 7|30-(5 11|30-y)=3 19|30

Answer 1

$7\frac{7}{30}-(5\frac{11}{30}-y)=3\frac{19}{30}$

 

$7\frac{7}{30}-5\frac{11}{30}+y=3\frac{19}{30}$

 

$1\frac{26}{30}+y=3\frac{19}{30}$

 

$y=3\frac{19}{30}-1\frac{26}{30}$

 

$y=1\frac{23}{30}$

Answer 2

7 7/30-(5 11/30-у)=3 19/30

7 7/30-3 19/30=5 11/30-y

5 11/30-y=3 18/30

5 11/30-3 18/30=y

y=1 23/30

ОТВЕТ: 1 23/30