<span>ω(N) в NH3 = M(N)/M(NH3) = 14/18*100% = 77.8%
</span><span>ω(S) в H2SO4 = M(S)/M(H2SO4) = 32/98*100% = 32.65%
</span><span>ω(C) в CO2 = M(C)/M(CO2) = 12/44*100% = 27.3 %
</span><span>ω(Na) в NaOH = M(Na)/(NaOH) = 23/40*100% = 57.5%</span>
CnH2n-6 + O2 -> nCO2 + (n-3)H2O
1 n
n(CO2)=8,96/22,4=0,4;
n(CnH2n-6) = 0,4/n;
M(CnH2n-6)=5,3n/0,4=13,25n;
12n+2n-6=13,25n
0,75n=6
n=8;
Ответ: C8H10
1)CH4+Cl2 --->(hn(квант света))CH3Cl + HCl (в скобках - условия превращения)
2) 2CH3Cl + 2Na ----> С2H6 +2NaCl
3) C2H6---->(Ni, t) C2H4 + H2
4)C2H4 + H2O ---> (H2SO4) C2H5OH
1)C2H4--->(Ni, t) C2H2 + H2
2)3C2H2--->(400-500 гр, C(уголь активированный)) C6H6
3)C6H6 + Cl2 ---> (FeCl3) C6H5Cl + HCl
4) C6H5Cl + NaOH ----> C6H5OH + NaCl
При20°С:
100г р-ра содержит 35,9г соли
50 г р-ра содержит Х г соли
100г--->35.9г
50 г--->Х г
Х=50*35,9/100=35,9/2=17,95г (NaCl)
Ответ:
Объяснение:
Mr(H2S) = 1*2 + 32 = 34
W(H) = Ar(H) *n / Mr(H2S) *100% = 1*2 / 34 *100% =6%
W(S) = Ar(S) *n / Mr(H2S) *100% = 32 *1 / 34 *100% = 94%
Mr(CS2) = 12 + 32*2 =76
W(C) = Ar(C) *n / Mr(CS2) *100% = 12*1 / 76 *100% =16%
W(S) = Ar(S) *n / Mr(CS2) *100% = 32*2 / 76 *100% = 84%
Mr(CaSO4) = 40 + 32+16*4 =136
W(Ca) = Ar(Ca) *n / Mr(CaSO4) *100% = 40*1 / 136 *100% =29%
W(S) = Ar(S) *n / Mr(CaSO4) *100% = 32*1 / 136 *100% = 23%
W(O) = Ar(O) *n / Mr(CaSO4) *100% = 16*4 / 136 *100% =48%
Mr(Na2SO4) = 23*2 + 32 + 16*4 =142
W(Na) = Ar(Na) *n / Mr(Na2SO4) *100% = 23*2 / 142 *100% =32%
W(S) = Ar(S) *n / Mr(Na2SO4) *100% = 32*1 / 142 *100% = 22%
W(O) = Ar(O) *n / Mr(Na2SO4) *100% = 16*4 / 142 *100% = 46%
Mr(Fe2(SO4)3 = 56*2 + 32*3 + 16*12 = 342
W(Fe) = Ar(Fe) *n / Mr(Fe2(SO4)3 *100% = 56*2 / 342 *100% =33%
W(S) = Ar(S) *n / Mr(Fe2(SO4)3 *100% = 32*3 / 342 *100% =28%
W(O) = Ar(O) *n / Mr(Fe2(SO4)3) *100% = 16*4 / 342 *100% = 39%
