2)f'(x)=(4sinx)'=4cosx;
f'(-2п/3)=4соs(-2п/3)=4×(-1/2)=-2;
3)f'(x)=[-3(x+2)-(2-3x)]/(x+2)^2=
(-3x-6-2+3x)/(x+2)^2=-8/(x+2)^2;
f'(-1)=-8/(-1+2)^2=-8/1=-8.
22 июн. 1941 г. – 9 мая 1945 г.
Правильный ответ я думаю будет 84
Решение
№ 104.
(tg³x - tg³y) / [(1 + tgxtgy)(tg²x + tgxtgy + tg²y)] =
= [(tgx - tgy)*(tg²x + tgxtgy + tg²y)] / [(1 + tgxtgy)(tg²x + tgxtgy + tg²y)] =
= (tgx - tgy) / (1 + tgxtgy) = tg(x - y)
№105.
(cos⁴2a - sin⁴2a) / (cos4a) - (cos2a - sin2a)² =
= [(cos²2a - sin²2a) * (cos²2a + sin²2a)] / (cos4a) - (cos²2a - 2sin2acos2a + sin²2a) = (cos²2a - sin²2a) / cos4a - 1 + 2sin2acos2a =
= cos4a / cos4a -1 + sin4a = 1 - 1 + sin4a = sin4a
№ 106.
[ 1/(1 - tgx) - 1/(1 + tgx)] * (cos²x - sin²x) =
= (1 + tgx - 1 + tgx)*cos2x / (1 - tg²x) =
= [2tgx*(1 - tg²x)] (1 - tg²x)(1 + tg²x)] = 2tgx / (1 + tg²x) = sin2x