Question

Всё на фото, решить понятно пожалуйста)

Answer 1

(1-㏒₂12)(1-㏒₆12)=(㏒₂2-㏒₂12)(㏒₆ 6 -㏒₆12)=㏒₂2/12 *㏒₆6/12=

= ㏒₂1/6 *㏒₆1/2=㏒₂ 6⁻¹ *㏒₆2⁻¹=-㏒₂6 *(- 1/ (㏒₂6 ))=1

6㏒₇√7= 6* (1/2)㏒₇7=3*1=3

㏒_⁶√13 (13)=㏒₁₃¹/⁶ 13= 6*㏒₁₃ 13=6*1=6

Answer 2

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