Question

Решите .........................................

Answer 1

$(2 a^{2} b^{-3}) ^{3} * ( \frac{1}{2} x^{-3} y^{-2} ) ^{-2} = 8 a^{6} b^{-9} * 4 x^{6} y^{4} = \frac{32}{ b^{9} } a^{6} x^{6} y^{4}$

Answer 2

( 2а²в-³)³×(1/2х-³у-²)-²=2³а^6×в^-9×(1|2)-²x^6y^4=8×4a^6×X^6/в^9=
=32(ax)^6×y^4/в^9