1) 3Ca(OH)2 + 2H3PO4 (разб.) = Ca3(PO4)2↓ + 6H2O
2) H3PO4 (конц.) + Ca(OH)2 = CaHPO4↓ + 2H2O
3) 2H3PO4 (конц.) +Ca(OH)2=Ca(H2PO4)2+2H2O
200г---5%
mг---10%
m=200*10/5=400г
Ответ:
дано
m(ppa CaCL2) = 140 g
W(CaCL2) = 10%
m2(CaCL2) = 10 g
m(H2O) = 25 g
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W2(CaCL2)-?
m(ppa CaCL2) = m(ppa CaCL2) + m2(CaCL2) + m(H2O)
m общая (ppa CaCL2) = 140 + 10+25 = 175 g
m1(CaCL2) = 140 * 10% /100% = 14 g
m общая (CaCL2) = m1(CaCL2) + m2(CaCL2) = 14+10 = 24 g
W2(CaCL2) = m общая (CaCL2) / m общая (ppa CaCL2) *100%
W2(CaCL2) = 24 / 175 * 100% = 13.7%
ответ 13.7%
Объяснение: