Cos7,ctg7;sin7;1
--------------------------------------
F(x)=(5x-3)³
f `(x)=3*(5x-3)²*(5x-3)`= 3(5x-3)²*5=15(5x-3)²
(х+у)^4 при х=0,7 и у=0,3 (0,7+0,3)^4=1^4=1
(х+у)^4 при х=-11 и у=6 (-11+6)^4=(-5)^4=625
(у-х)^3 при х=-14 и у=-10 (-10-(-14))^3=4^3=64
(у-х)^3 при х=0,9 и у=1,1 (1,1-0,9)^3=0,2^3=0.008
B3 = b1*q^2 = 18
b1*3^2 = 18
b1*9 = 18
b1 = 2
S5 = (b1*(1-q^5))/(1 - q) = (2*(1-3^5))/(1-3) = 242