Question

Помогите пожаоуйста ответить на г) д) ж) з) е) желательно чтобы решение было фоткой, в тетради

Answer 1

Г)
$8 \frac{1}{12} - 3 \frac{4}{15} - 1 \frac{7}{30} = \\ = 8 \frac{5}{60} - 3 \frac{16}{60} - 1 \frac{14}{60} = \\ = 7 \frac{65}{60} - 3 \frac{16}{60} - 1 \frac{14}{60} = \\ = 3 \frac{35}{60} = 3 \frac{7}{12}$
д)
$(13 - 8 \frac{5}{12} ) + (17.5 - 16.2) = \\ = 4 \frac{7}{12} + 1.3 = \\ = 4\frac{35}{60} + 1 \frac{18}{60} = \\ = 5 \frac{53}{60}$
ж)
$(15.5 - 2.375) - (5 \frac{20}{24} + 6 \frac{18}{24} ) + (10 \frac{16}{24} - 5 \frac{15}{24} ) = \\ = 13.125 - 12 \frac{2}{3} + 5 \frac{1}{24} = \\ = 13.125 - 12 \frac{16}{24} + 5 \frac{1}{24} = \\ = 13 \frac{125}{1000} - 12 \frac{16}{24} + 5 \frac{1}{24} = \\ = 13 \frac{3000}{24000} - 12 \frac{16000}{24000} + 5 \frac{1000}{24000} = \\ = 12 \frac{27000}{24000} - 12 \frac{16000}{24000} + 5 \frac{1000}{24000} = \\ = \frac{12000}{24000} = \frac{1}{2} = 0.5$
з)
$0.25 + 0.75 + (1 \frac{36}{24} - \frac{17}{24}) = \\ = 1 + 1 \frac{19}{24} = 2 \frac{19}{24}$
е)
$(63 \frac{16}{24} + 3 \frac{3}{24} ) - 2 \frac{4}{9} = \\ = 66 \frac{19}{24} - 2 \frac{4}{9} = \\ = 66 \frac{57}{72} - 2 \frac{32}{72} = \\ = 64 \frac{25}{72}$