Б.27.3%
CO2.
ω=Ar(C)/Mr(CO2)·100%=12/44·100%=27.3%
W(в-ва)=m(в-ва)/m(р-ра)*100%
m(H2SO4)=200г
m(р-ра)=2.7+200=202.7г
w(H2SO4)=200/202.7=0.986=98.6%
2 вар-а:
а) <span>
CuO + NaH = Cu + NaOH и
б) </span><span>2CuH + Cu2O = 4Cu + H2O.</span>
2HCl + BaO -> BaCl2 + H2O
3KOH + H3PO4 -> K3PO4 + 3H2O
FeO + H2SO4 -> FeSO4 + H2O
CO2 +2 Mg -> 2MgO + C