- x^2 = - 2x + 2
x^2 - 2x + 2 = 0
D = 4 - 4*2 = 4 - 8 <0
нет реш
∫(5+х)/(3x^2+1)dx
∫(x/3x²+1)+(56/3x²+1)dx={u=3x²+1; du=6xdx;dx=du/6x}=1/6∫du/u+5∫dx/(3x²+1)=
=logu/6+{s=√3dx}=logu/6+5/√3∫ds/(s²+1)=5tg⁻¹(s)/√3+logu/6=
=1/6log(3x²+1)+5tg⁻¹(√3x)/√3+c
Ответ:36с^2
Объяснение:36c^2+24c+4=
=(6c)^2+2×6с×2+2^2=(6c+2)^2
(x + 2)² = 13 - (x - 3)²
x² + 4x + 4 = 13 - (x² - 6x + 9)
2x² - 2x = 0
2x(x - 1) = 0
x₁ = 0 x₂ = 1
Ответ: {0; 1}