2Mg+O₂<span>=2MgO
n(Mg)=12/24=0.5моль
</span>n(Mg):n(O₂)=2:1=0.25
V(O₂)=0.25*22.4=5.6л
1) MgO + CO₂ --> MgCO₃
2) 2NaOH + SO₂ --> Na₂SO₃ + H₂O
3) Al₂O₃ + 3SO₃ (t) --> Al₂(SO₄)₃
4) Fe(OH)₃ + 3HNO₃ --> Fe(NO₃)₃ + 3H₂O
5) 3KOH +H₃PO₄ --> K₃PO₄ + 3H₂O
6)CiSO4(?)-->FeSo4-->Fe(OH)2-->Fe(NO3)2-->CO2
H₂SO₄ + Fe = FeSO₄ + H₂↑
FeSO₄ + 2NaOH = Fe(OH)₂↓+ Na₂SO₄
Fe(OH)₂ + 2HNO₃(разб.) = Fe(NO₃)₂ + 2H₂O
Fe(NO₃)₂ + K₂CO₃ = FeCO₃↓ + 2KNO₃
FeCO₃ + 2HCl = FeCl₂ + H₂O + CO₂↑
Дано:
<span>m
(C2H6) = 3 г</span>
найти:
<span>V
(C2H4)</span>
Решение:
<span>
х л 3 г</span><span>
C2H4 + H2 =
C2H6</span><span>
22,4 л 30 г</span>
<span>х л ------- 3 г</span>
<span>22,4 л -----30
г
</span><span>х = 3г ∙ 22,4 л\30г = 2,24 л</span>
<span>Pb(NO3)2
Mr(</span><span>Pb(NO3)2)=85+14*2+16*6=209
w(Pb)=85/209*100\%=41\%
w(N2)=28/209*100\%=13\%
w(O2)=96/209*100\%=46\%
</span>